Three consecutive odd integers have a sum of 45. Find the integers.

13, 15, 17

Step-by-step explanation:

Each digit must be odd, and to get consecutive odd integers, you must add using the multiple of 2:

Let the least number be "x". Set the equation:

(x) + (x + 2) + (x + 4) = 45

Isolate the variable, x. First, combine like terms:

(x + x + x) + (2 + 4) = 45

(3x) + 6 = 45

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Subtract 6 from both sides:

3x + 6 (-6) = 45 (-6)

3x = 45 - 6

3x = 39

Divide 3 from both sides:

(3x)/3 = (39)/3

x = 39/3

x = 13

Your first number (x) is 13. Solve for the other 2 numbers:

(x) = 13

(x + 2) = 13 + 2 = 15

(x + 4) = 13 + 4 = 17

13, 15, 17 are your numbers:

Check:

13 + 15 + 17 = (13 + 15) + 17 = 28 + 17 = 45

~

idk

step-by-step explanation:

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0