Calculate the size of the largest angle in the triangle. Give your answer to an appropriate degree of accuracy.

110.9° = 111°

Step-by-step explanation:

Given ∆ABC, where

length of side AB = 15 cm,

length of side AC = 7 cm

length of side BC = 11 cm

Required:

Size of largest angle in ∆ABC

SOLUTION:

The size of the largest angle in the triangle is the angle that has the largest side length opposite it.

Therefore, the largest angle in ∆ABC = <C, which has a side length of 15 cm opposite it.

=>Find the angle of C using the Law of Cosine

Cos C = (a² + b² - c²)/2ab

Cos C = (11² + 7² - 15²)/2*11*7

Cos C = (121 + 49 - 225)/154

Cos C = -55/154

Cos C = -0.3571

C = Cos-¹(-0.3571)

C = 110.9° ≈ 111°

my acc plz

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!