g A canyon is 1200 meters deep at its deepest point. A rock is dropped from the rim above this point. How long will it take the rock to hit the canyon floor

t = 15.6 s

Step-by-step explanation:

According to the kinematic equation:

  (1)

Where:

: is the final position = 1200 m

y₀: is the initial position = 0 m

V₀: is the initial speed = 0 m/s

g: is the gravity = 9.81 m/s²

t: is the time =?

From equation (1) we have:

Therefore, it will take 15.6 seconds to the rock to hit the canyon floor.

I hope it helps you!

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.