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1. 29.44 feet.

2. 2/3.

3. 10/9.

4. 39/5.

Step-by-step explanation:

1. 34-foot ladder makes a 60 degree angle with the ground. If you visualize a 30-60-90 triangle with the ladder and the building and the ground, you can see that the hypotenuse of the triangle is 34 feet.

With 30-60-90 triangles, the short side is x, the hypotenuse is 2x, and the long side is x and the square root of 3.

If the hypotenuse is 34 feet, that must mean that the short side is 34 / 2 = 17 feet. The long side will be 17 * sqrt(3) = 17 * 1.732050808 = 29.44486373. So, the height above the ground will be about 29.44 feet.

2. Tangent of A! For this, we will use SOH CAH TOA... TOA stands for tangent: opposite over adjacent.

According to the diagram, angle A has an adjacent side of 15 units and an opposite side of 10 units. That means that tanA = 10 / 15 = 2/3.

If you want to find the measure of angle A, you can easily find the cotangent of 2/3. That is 33.69006753, or about 34 degrees.

3. The ratio should be 5 feet to 54 inches. There are 12 inches in 1 foot, so 5 feet is the same thing as 60 inches. 60 / 54 = 30 / 27 = 10/9.

4. (p + 9) / 7 = 12 / 5

5(p + 9) = 12 * 7

5p + 45 = 84

5p = 39

p = 7.8

That is the same thing as 7 and 4/5, or (35 + 4)/5 = 39/5

Really hope this helps!!

Answer to #4:a=−p2+84/p (note:the p2 is p to the exponent of 2, not p times 2)

Explanation:

Step 1:Multiply both sides by p

1/7ap+1/7p2=12

Step 2:Step 2: Add (-1)/7p^2 to both sides.

1/7ap+1/7p2+(−1/7p2)=12+(−1/7p2)1/7ap=−1/7p2+12

1/7ap=−1/7p2+12

Step 3: Divide both sides by p/7. and you get..

a=−p2+84/p

note:the p2 is p to the exponent of 2, not p times 2

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.