What is the center of a circle whose equation is x2 + y2 – 12x – 2y + 12 = 0? A. (–12, –2) B. (–6, –1) C. (6, 1) D. (12, 2)

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph