A line passes through the point (12,0) and is parallel to the line with the equation y = x + 1. What's the equation of the line? A. y = 6x + 5
B. y= -6x
C. y= -1/6x-1
D. y = 1/6x-2

y = x - 12

Step-by-step explanation:

Since the lines are parallel, the slopes are the same.

The desired equation has the form y = x + 1.  Replacing the constant (1) by C, we get y = x + C.  Finally, we substitute 12 for x and 0 for y in y = x + C to determine the value of C:

0 = 12 + C, or C = -12

Then the equation of the line is y = x - 12.

828. all there is to it!

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