AABC has vertices at A(12, 8), B(4,8), and C(4, 14). AXYZ has vertices at X(6, 6), Y(4, 12), and Z(10, 14).

AMNO has vertices at M(4. 16), N(4.8), and O(-2.8).

AJKL has vertices at J(14, -2), K(12, 2), and L(20, 4).

are congruent. A

is a single rigid transformation that maps the two congruent triangles.

Triangle ABC and triangle XYZ

Triangle ABC and triangle MNO

Triangle JKL and triangle ABC

Triangle MNO and triangle XYZ

Triangle ABC and triangle MNO are congruent. A Rotation is a single rigid transformation that maps the two congruent triangles.

Step-by-step explanation:

ΔABC has vertices at A(12, 8), B(4,8), and C(4, 14).

ΔMNO has vertices at M(4, 16), N(4,8), and O(-2,8).

Therefore:

and ΔABC ≅ ΔMNO by SSS postulate.

In the picture attached, both triangles are shown. It can be seen that counterclockwise rotation of ΔABC around vertex B would map ΔABC into the ΔMNO.

21/58.

hope to be marked brainliest

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic