The ratio of the lengths of the corresponding sides of two regular octagons is 8 to 3. The area of the larger octagon is 320 ft2. Find the area of the smaller octagon.

45 square units

Step-by-step explanation:

In the above question, we are given the following values

The ratio of the lengths of the corresponding sides of two regular octagons is 8 to 3.

This means the length of the larger octagon = 8

The length of the smaller octagon = 3

Using scale factor denoted as k and because we are dealing with area of the octagon

k = 3²/8²

The area of the larger octagon is 320 ft².

The area of the smaller octagon s represented as y and is calculated as

k = y/Area of larger octagon

3²/8² = y/320

Cross multiply

8² × y = 3² × 320

y = 3² × 320/8²

y = 45 square units

Area of smaller octagon = 45 square units.

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