If cote = and the terminal point determined by a is in quadrant 3, then: A. tang = 1
O B. csco = -
Lolo
DC. sing -
ml
O D. Cose =
3
5

The correct option is:

cosθ = -3/5

Step-by-step explanation:

We have been given that:

cotθ = 3/4

such that the terminal side of θ lies in III quadrant.

Consider it a right angled triangle.

We know that:

cotθ = Base / Perpendicular

Which means Base has a magnitude of 3 and Perpendicular has the magnitude of 4.

As It lies in III quadrant, both x and y are negative.

So

Base = -3

Perpendicular = -4

Find the hypotenuse by using Pythagoras Theorem

H² = (-3)² + (-4)²

H = 5

We know that:

cosθ = Base / Hypotenuse

cosθ = -3/5

i dont understand the question? ?

step-by-step explanation:

exa:

)

3+11

14

step-by-step explanation:

from this example, we can see that subtracting with integers is the same as adding the opposite. we can solve using a number line or by using the saying "keep, change, change" to us solve. it is important to remember that we can subtract a negative and end up with a larger number than we started with.