Someone help me pls, will give brainiest and high points

Step-by-step explanation:

Using sine rule on triangle ABC as re - shown in the attachment below to get side AC first we have;

∠A = 34°, BC = 164cm, ∠B = 27°, AC = ?

AC/sin 27° = BC/sin 34°

AC/sin 27° = 164/sin 34°

AC = 164 * sin 27° / sin 34°

AC = 74.45/0.5592

AC = 133.14 cm

To get the side 'a', we will use the trig ratio SOH CAH TOA on the right angled ACD.

According to SOH,

sin 61° = a/AC

a = ACsin61°

a = 133.14 * sin 61°

a = 116.45

a ≈ 117 cm

The marked side is approximately 117 cm

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."