If P and Q are two sets such that P U Q has 40 elements, P has 22 elements and Q has 28 elements, how many elements does P intersection Q have

Step-by-step explanation:

n(P∪Q) = 40

Using Formula

n(P∪Q)=n(P)+n(Q)−n(P∩Q)

For, n(P∩Q), it becomes

=> n(P∩Q)=n(P)+n(Q)−n(P∪Q)

So,

=> n(P∩Q) = 22+28-40

=> n(P∩Q) = 50-40

=> n(P∩Q) = 10 elements

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%

your answer is 228

step-by-step explanation:

add the top and bottom bases together, then divide them by 2, then multiply by the height.