HELP! Find the 11th term in the geometric sequence in which a3 is 24 and a5 is 96

a₁₁ = 6144

Step-by-step explanation:

The n th term of a geometric sequence is

= a₁

where a₁ is the first term and r the common ratio

Given a₃ = 24 and a₅ = 96 , then

a₁r² = 24 → (1)

a₁ = 96 → (2)

Divide (2) by (1)

= , that is

r² = 4 , thus

r = 2

substitute r = 2 into (1)

4a₁ = 24 ( divide both sides by 4 )

a₁ = 6

Thus

a₁₁ = 6 × = 6 × 1024 = 6144

step-by-step explanation:

so first find out how much each is worth.

quarter= 25 cents

dime= 10 cents

pennies= 1 cent

then multiply each by how much each is worth.

200                     150                   300

x                         x                     x   1

  25                       10              

                                  300

1000                     1500

+                          

4000                                      

5000                                  

then count 2 from the back and add a period.

$50.00

$15.00

$3.00

and then add them

  $50.00

+

  $15.00

+

    $3.00

$68.00

so sunghee has $68.00

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36 girls

step-by-step explanation:

the 48 boys is 4 parts of the ratio

divide 48 by 4 to obtain one part of the ratio

= 12 ← 1 part of the ratio

3 parts = 3 × 12 = 36 ← number of girls