Consider triangle ABC. Triangle A B C. Angle C is 80 degrees and angles B and A are y degrees. What is the value of y in the triangle? Angle y = °

y= 50°

Step-by-step explanation:

∠A =∠B = y. So, ΔABC is an isosceles triangle.

Sum of angles of triangle = 180

∠A + ∠B + ∠C = 180

y + y + 80 = 180   {add like terms}

2y + 80 = 180  {Subtract 80 from both sides}

2y + 80 - 80 = 180 - 80

2y = 100   {divide both sides by 2}

2y/2 = 100/2

y= 50°

the answer on e2020 is

10

4/5

3/5

4/3

step-by-step explanation:

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation: