Express the confidence interval 0.333 less than p less than 0.999 in the form Modifying Above p with caret + or - E. Modifying Above p with caret + or - E = + or -.

We are being asked to express the confidence interval " " in the form . Well, just take a look at procedure below for the first half of the problem,

As you can see, for this first bit we took the average of the numbers, for the second we subtracted one from the other, and now let us approximate each value -

And so, should be . That is our solution!

total of apples - take away four

6-4 = 2

answer is 2 apples

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

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m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0