What is the perimeter of a parallelogram, if it's area is 36 cm^2 and the distances between the point of intersection of the diagonals and the sides are 2 cm and 3 cm? PLEASE HELP QUICK

The perimeter of a parallelogram is 30cm.

Step-by-step explanation:

From the question , the given area of a parallelogram is 36 cm².

But the area of a parallelogram can be calculated using below formula

Area = base * height

From the question the distances that exist between the point of intersection of the diagonals and the sides are 2cm and 3cm respectively

There is the same distance between point of intersection of the diagonals and the opposite sides then,

The base of the side with 4cm can be calculated as

ha= 2+ 2= 4cm

But area can be calculated as A= base × height

36= b1 × h1

36=b1 × 4

b1= 9cm

The base of the other side can be calculated with 6cm height

h2= 3+3=6cm

A= b2× h2

36= b2 ×h2

36= b2× 6

b2= 6cm

Then the perimeter of the parallelogram can be calculated as

P= 2(b1 + b2)

= 2(6+9)

= 30cm

Hence,the perimeter of the parallelogram is 30cm

step-by-step explanation:

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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