What is the biggest whole number smaller than the perimeter of any triangle with a side of length 5.6 and a side of length 19.7?

50

Step-by-step explanation:

The perimeter of a Triangle is the sum of it's 3 sides.

We are given two sides here which is side length 5.6 and a side of length 19.7

Let's us represent the third side as x

Therefore

x + 19.7 + 5.6 = Perimeter of the triangle

We would have this equation

But it is important to know that every side of a triangle must be less than the sum of the other two sides, hence

x < 19.7 + 5.6

x < 25.3

Adding 25.3 to both sides to make the left side equal to the perimeter

perimeter = x+25.3 < 25.3 + 25.3 = 50.6

Therefore, 50.6 is the smallest whole number that is larger than the perimeter of the triangle in the question above.

Therefore, the biggest whole number smaller than the perimeter of the above triangle is 50

the answer is n

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )