he graphed line shown below is y = 3 x minus 1. On a coordinate plane, a line goes through (0, negative 1) and (1, 2). Which equation, when graphed with the given equation, will form a system that has an infinite number of solutions? y + 1 = 3 x y = negative 3 x + 1 y = 3 x + 1 y minus 3 x = negative 3

y + 1 = 3x

Step-by-step explanation:

The graphed line is y = 3x - 1

The options given to us are

y + 1 = 3x

y = -3x + 1

y = 3x + 1

y - 3x = -3

Consider the first equation:

y + 1 = 3x

Substitute (0,-1) into the equation:

-1 + 1 = 3(0)

0=0

Substitute (1,2) into the equation:

2+1 = 3(1)

3 = 3

Thus the equation holds true for the given points.

Rearrange the equation

y + 1 = 3x

y = 3x - 1

As it is the same equation which was initially graphed, both of these lines will be same and overlap each other, resulting in infinite number of solution

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10