A labourer is paid Rs per hr for an 8- hr day and1/2 times the rate for
each hour in excess of 8 hrs in a
sigle day the received
Rs.80 for a single days work, how
long did he work on that day?

Complete question is;

A labourer is paid rs. 8 per hour for an 8 hour day and ½ times that rate for each hour in excess of 8 hours in a single day. if the labourer received rs. 80 for a single day's work, how long did he work on that day?

Total working time for the day = 12 hours

Step-by-step explanation:

Money paid to the labourer for initial 8 hrs of work = 8 × 8 = rs. 64.

Now, we are told that he receives rs. 80 in total for that day. And that he receives ½ times the initial rate for each extra hour after the initial 8 hour period.

Thus;

½ × 8 × y = (80 - 64)

Where y is the duration of extra hours.

So;

4y = 16

y = 16/4 hours

y = 4 hours

Now, since extra hours = 4 hours and normal working hours = 8 hours.

Then, total working time for that day = 8 + 4 = 12 hours