![x^2-\dfrac{2}{3}x= (x-\dfrac{1}{3})^2-\dfrac{1}{9} \ so\\15x^2-10x=15(x^2-\dfrac{2}{3}x)=15[(x-\dfrac{1}{3})^2-\dfrac{1}{9} ]=15(x-\dfrac{1}{3})^2-\dfrac{15}{9}\\=15(x-\dfrac{1}{3})^2-\dfrac{5}{3}](/tpl/images/0707/8478/b8ca1.png)
What must be added to
15x²-10x to make it
perfect square
a...
Answers: 2
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