Tublu buys a cylindrical water tank of height 1.4m and diameter 1.1m to catch rainwater off his roof. He has a full 2 litres tin of paint in his store and decides to paint the tank (not the base). If he uses 250 ml to cover 1 m2, will he have enough paint to cover the tank with one layer of paint? [take π=3.142]

Tublu has more than enough paint to cover the tank surface in one layer coating

Step-by-step explanation:

Height of the cylinder = 1.4 m

diameter of the cylinder = 1.1 m

total volume of paint available = 2 litres

It takes 250 ml to cover 1 m^2 of the tank body

Since only the body is to be painted, we find the perimeter of the circle formed by the body of the tank.

perimeter of the circle formed by the body of the  tank =

==> 3.142 x 1.1 = 3.456 m

This perimeter, if spread out, will form a rectangle with a height of 1.4 m from the base.

The area of the rectangle that will be formed =  (perimeter of the cylinder body) x ( height of the cylinder)

==> 3.456 x 1.4 = 4.838 m^2

This is the area that needs to be painted.

Converting the paint volume,

250 ml = 0.25 litres

To paint the above calculated are, we will need 4.838 x 0.25 = 1.21 litres of paint, (of course, excluding the base)

The volume of paint available = 2 litres

volume of paint needed = 1.21 litres

Tublu has more than enough paint to cover the tank surface in one layer coating

my answer got deleted but it's a

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.