What is the length of line segment RS? Use the law of sines to find the answer. Round to the nearest tenth. Triangle Q R S is shown. Angle Q R S is 80 degrees. The length of Q R is 2.4 and the length of Q S is 3.1. Law of sines: StartFraction sine (uppercase A) Over a EndFraction = StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction 2.2 units 2.4 units 3.0 units 3.3 units

2.4 UNITS

Step-by-step explanation:

The sine rule :

Sine A / a = Sine B / b = Sine C / c

From the diagram attached :

QR = s = 2.4 ; QS =r = 3.1 ; RS =q =?

We need to find the angle RQS

using Sine rule :

Sine R / r = Sine S / s

Sin 80° / 3.1 = sin S / 2.4

0.9848077 / 3.1 = sin S / 2.4

Sin S × 3.1 = 0.9848077 × 2.4

Sin S = 2.3635386 / 3.1

Sin S = 0.7624318

S = Sin^-1(0.7624318)

S = 49.67°

Therefore, form using ;

A + B + C = 180° ( SUM of angles in a triangle)

SQR = 180° - (QRS + QSR)

= 180° - ( 80 + 49.67)° = 50.33°

Q = 50.33°

THEREFORE,

Sine Q / q = Sin S / s

Sin 50.33° / q = Sin 49.67° / 2.4

0.7697339 / q = 0.7623295 / 2.4

0.7623295q = 0.7697339 × 2.4

q = 1.84736136 / 0.7623295

q = 2.4233108

q = Segment RS = 2.4units

B) 2.5 is the right answer

Step-by-step explanation:

i got 100%

a c

step-by-step explanation: