Find the range of ƒ(x) = 3x – 5 for the domain {–1.5, 2, 4}.

{-9.5, 1,7}

Step-by-step explanation:

For y =f(x)

domain is list of all values of x and range is list of all values of y

Given

ƒ(x) = 3x – 5

domain = {–1.5, 2, 4}.

thus,

range will be value of f(x)

when x = -1.5

x = 2 and x = 4

Thus,

for x = -1.5

ƒ(x) = 3*-1.5 – 5 = -4.5 - 5 = -9.5

\

for x = 2

ƒ(x) = 3*2– 5 = 6 - 5 = 1

for x = 4

ƒ(x) = 3*4– 5 = 12 - 5 = 7

thus,

range of ƒ(x) = 3x – 5 is {-9.5, 1,7}

answer: dead jah

step-by-step explanation:

bullet + jah= dead jah

so, converting firstly the mixed fractions to improper fractions and then "adding".