Which equation has the solutions x = 1 plus-or-minus StartRoot 5 EndRoot? x2 + 2x + 4 = 0 x2 – 2x + 4 = 0 x2 + 2x – 4 = 0 x2 – 2x – 4 = 0

x^2 - 2x - 4 = 0.

Step-by-step explanation:

Written in factor form we have:

(x - ( 1 + √5)( x - (1 - √5)) = 0

(x - 1 -√5)( x - 1 +√5)) = 0        Expanding:

x^2 - x +√5x  - x + 1 - √5 - √5x + √5 - 5 = 0

x^2 - 2x - 4 = 0.

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step-by-step explanation:

yes   because as the functions are graphed they eventually will intersect unless otherwise

step-by-step explanation: