Write a pair of integers whose difference gives. (a) a negative integer. (b) zero. (c) an integer smaller than both the integer. (d) an integer smaller than only one of the integers. (e) an integer greater than both the integers.

(a)5 and 8

(b)5 and 5

(c) 7 and 5

(d)6 and 2

(e)6 and -2

Step-by-step explanation:

(a)a negative integer

We consider the integers 5 and 8

Difference = 5-8 =-3

3 is a negative integer.

(b)Zero

We consider the integers 5 and 5

Difference = 5-5 =0

(c) an integer smaller than both the integer.

We consider the integers 7 and 5

Difference = 7-5 =2

2 is smaller than both integers.

(d) an integer smaller than only one of the integers.

We consider the integers 6 and 2

Difference =6-2=4

4 is smaller than only 6.

(e)an integer greater than both the integers

We consider the integers 6 and -2

Difference =6-(-2)=6+2=8

8 is greater than both 6 and -2.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.