Abigail was skateboarding home when the wheel axle of her skateboard broke. She had already traveled two-thirds of the way home and had to walk the rest of the way. Walking the rest of the way home took her twice as long as it took her to ride her skateboard. How many times faster is Abigail on her skateboard than she is walking?

4 times faster

Step-by-step explanation:

From the above question, we have the following information

Let us represent the Distance traveled by Abigail as Y

On her skateboard she travelled two thirds of the way = 2/3Y

She walks the rest of the way home = Y - 2/3Y = 1/3Y

The time she used to walk home is twice the time she used to ride her skate board

Hence, let us represent the time she used to ride her skateboard as S

So, Time she used to walk home = 2 × S = 2S

The question is asking us, how fast ,this is = Speed

The formula for Speed = Distance/ Time

Speed for her skate board = 2/3Y/S = 2Y/3S

Speed as she walks = 1/3Y / 2S = Y/ 6S

How many times faster is Abigail on her skateboard than she is walking is calculated as :

Speed of Abigail while skating ÷ Speed of Abigail while walking

= 2Y/3S ÷ Y/6S

= 2Y/3S × 6S/Y

= 4

Therefore, Abigail was 4 times faster on her skateboard than she is walking.

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

step-by-step explanation:

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