Abigail was skateboarding home when the wheel axle of her skateboard broke. She had already traveled two thirds of the way home and had to walk the rest of the way. Walking the rest of the way home took her twice as long as it took her to ride her skateboard. How many times faster is Abigail on her skateboard than she is walking?

4 times faster

Step-by-step explanation:

Let us represent the Distance to Abigail home as D

On her skate board Abigail covered the distance of 2/3D

The distance left = 1 - 2/3 = 1/3D

Abigail will walk the distance 1/3D home

To cover 1/3, it takes Abigail 2 times the time it took for her to ride her skate board

Let T be the time it takes for Abigail to skate

Therefore, it takes Abigail 2T times to walk home.

Speed = Distance / Time

For Skating,

= (2/3)D/T = 2D/3T

For walking

Speed = (1/3)D/2T= D/6T

When we compare the speed of both the skating and walking to find out how fast she was when skating, we have to divide the speed of her skating by her speed when she was walking

2D/ 3T ÷ D/6T

2D/3T × 6T/D

= 4

Therefore, Abigail was 4 times faster on her skate board

37

step-by-step explanation:

step-by-step explanation:

ask goog great chance of finding the solution there