In the diagram shown, FJ bisects AD BL~=LC. The length of BL is 10 less than the length of AB. The length of AD is 220. What is the length of BD?

Option (C)

Step-by-step explanation:

Since FJ is the bisector of AD,

AL ≅ DL

And it's given that BL ≅ LC

Length of BL is 10 less than the length of AB.

m(BL) = m(AB) - 10

m(AD) = 220 [Since m(AD) = 2m(AL)]

2m(AL) = 220

m(AL) = 110

m(AB) + m(BL) = 110

m(AB) + [m(AB) - 10] = 110

2m(AB) = 110 + 10

m(AB) = 60

Therefore, m(BL) = m(AL) - m(AB)

                            = 110 - 60

                            = 50

Since, m(AL) = m(DL)

m(AB) + m(BL) = m(LC) + m(CD) [Since BL = LC]

m(AB) = m(CD) = 60

Now m(BD) = m(BL) + m(LC) + m(CD)

                   = 50 + 50 + 60

                   = 160

Therefore, option (C) will be the answer.

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following