A particle moves along line segments from the origin to the points (3, 0, 0), (3, 3, 1), (0, 3, 1), and back to the origin under the influence of the force field F(x, y, z) = z2i + 3xyj + 3y2k. Find the work done.

[8i + 54j + 72k] joules per newton metre square.

Step-by-step explanation:

F(x,y,z) = z2i + 3xyj + 3y2k

F(3,0,0) = 0

F(3,3,1) = 1(2i) + 3(3)(3)j + 3(3)(2k)

= 2i + 27j + 18k

F(0,3,1) = 1(2i) + 3(0)(3)j + 3(3)(2k)

= 2i + 18k

The sum = [4i + 27j + 36k]

Since the particle moves back to the origin, we multiply the above Work Done by 2:

[8i + 54j + 72k]

And since work done is the product of Force and Distance, the S.I. unit is Joules/newton metre square

people grow faster than other people.

step-by-step explanation:

should you really be posting this isn't math boi.

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3