The data points for equation A are graphed on the coordinate plane below and are connected by using a straight line. On a coordinate plane, a line goes through (0, negative 2) and (2, 4). What is the solution to the system of equations? (–2, –8) (–1, –5) (0, –2) (2, 4)

(–1, –5)

Step-by-step explanation:

Two linear equations are represented by using the tables below. A 2-column table with 4 rows titled Equation A. Column 1 is labeled x with entries negative 2, 0, 3, 4. Column 2 is labeled y with entries negative 8, negative 2, 7, 10. A 2-column table with 4 rows titled Equation B. Column 1 is labeled x with entries negative 3, negative 1, 1, 5. Column 2 is labeled y with entries negative 9, negative 5, negative 1, 7. The data points for equation A are graphed on the coordinate plane below and are connected by using a straight line. On a coordinate plane, a line goes through (0, negative 2) and (2, 4). What is the solution to the system of equations? (–2, –8) (–1, –5) (0, –2) (2, 4)

To find the equation of line A, we can use any two points. Let us use points (-2, -8) and (0, -2). Therefore, the equation of line A can be gotten using the equation:

To find the equation of line B, we can use any two points. Let us use points (-3, -9) and (-1, -5). Therefore, the equation of line B can be gotten using the equation:

To find the solution to the system of equations, we solve them simultaneously

y = 3x   - 2              .             .             .         1)

y = 2x - 3                .                .           .           2)

Subtracting equation 2 from 1:

x + 1 = 0

x = -1

Put x = -1 in equation 1)

y = 3(-1) - 2

y = -3 - 2

y = -5

Therefore the solution to the equation is (-1, -5)

the correct answer is B (–1, –5)

b

step-by-step explanation:

answer:

c) the x-coordinate of the center of the circle increases by 3