CAN SOMEONE PLEASE HELP ME THIS IS DUE SOON!!

95 ft²

Step-by-step explanation:

Given:

regular pyramid with,

Square base of side length (s) = 5 ft

Slant height (l) = 7 ft

Required:

Surface area

Solution:

Surface area of a regular pyramid = ½*P*l + B

Where,

P = perimeter of the square base = 4(s) = 4(5) = 20 ft

l = slant height = 7 ft

B = area of base = s² = 5² = 25 ft²

Surface area = ½*20*7 + 25

= 10*7 + 25

= 70 + 25

Surface area of regular pyramid = 95 ft²

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet