X= ?? geometry ??? And how ?

Using the equations for tangent and secant lines:

Let the unknown length of the line inside the circle = y

6^2 = 3 x (y+3)

Simplify:

36 = 3y+9

Subtract 9 from both sides:

27 =3y

Divide both sides by 3:

Y = 9

Now add to get x:

X = 9 + 3 = 12

X = 12

answer:

(-8,7)

explanation:

we know that  

f

(

−

3

)

=

7

therefore, if we wish to get the output as 7, in the function, we need to have our input to be -3.

looking at the function  

f

(

x

+

5

)

, what should the value of x be, such that the input in the function becomes 7?

we simply equate the terms,

x

+

5

=

−

3

x

=

−

8

thus, the point on the new function would be  

(

−

8

,

7

)