Please answer There is a bag filled with 3 blue and 5 red marbles. A marble is taken at random from the bag, the colour is noted and then it is not replaced. Another marble is taken at random. What is the probability of getting exactly 1 blue?

 is the required probability.

Step-by-step explanation:

Total number of Marbles = Blue + Red

Probability of getting blue

Probability of not getting a blue

To get exactly one blue in two draws, we either get a blue, not blue, or a not blue, blue.

First Draw Blue, Second Draw Not Blue:

1st Draw:

2nd Draw:  (since we did not replace the first marble)

To get the probability of the event, since each draw is independent, we multiply both probabilities.

First Draw Not Blue, Second Draw Not Blue:

1st Draw:

2nd Draw:  (since we did not replace the first marble)

To get the probability of the event, since each draw is independent, we multiply both probabilities.

To get the probability of exactly one blue, we add both of the events:

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."