Mathematics, 18.07.2020 20:01 bananaslada

5. Each year a tree farm grows 40 more trees than the number of trees grown the previous year. The farm sells all of their trees each season (or year). If the farm started out with 30 trees in 2007, how many trees were sold in total up to and including the 2016 season?

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Answer from: imthebestatcod

1710 trees up to 2016 (not including 2016)

2100 trees up to 2016 (including 2016)

Step-by-step explanation:

Given that

Farm started with 30 trees in 2007.

Every year 40 more trees than the previous year.

It is actually an Arithmetic Progression (AP) with

First term, a = 30 and

Common Difference, d = 40

The AP will look like:

30, 70, 110, 150, ....

We have to find the sum of this AP upto 9 terms and 10 terms:

9 terms sum will give us the total number of trees up to 2016 (not including 2016).

10 terms sum will give us the total number of trees up to 2016 (including 2016).

Formula for sum of 'n' terms of an AP:

$S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_9=\dfrac{9}{2}(2\times 30+(9-1)40)\\\Rightarrow S_9=\dfrac{9}{2}(60+320)\\\Rightarrow S_9=\dfrac{9}{2}(380)\\\Rightarrow S_9=9 \times 180 = 1710$

$S_{10}=\dfrac{10}{2}(2\times 30+(10-1)40)\\\Rightarrow S_{10}=5(60+360)\\\Rightarrow S_{10}=5 \times 420\\\Rightarrow S_{10}=2100$

1710 trees up to 2016 (not including 2016)

2100 trees up to 2016 (including 2016)

Answer from: Quest

a. since the profit made in 2012 is equal to the profit made in 2014, the profit is symmetric about the line y = 120,000.

step-by-step explanation:

Answer from: Quest

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