Pat is 2 years younger than his wife, Wynn. Ten years ago the sum of their ages was 48. How old are they now?

Pat is 33 and Wynn is 35

Step-by-step explanation:

x for pat and y for wynn

Pat is 2 years younger than his wife : x-2=y

Ten years ago the sum of their ages was 48 : x+y=48

substitute x-2 for y in the second equation:

x+y=48

x+x-2=48

2x=46

x=23 age of Pat ten years ago and Wynn=25

now Pat is 33 and Wynn is 35

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)