Which of the following is the correct factorization of the polynomial below 2x^2-16x+32 A. (2x+4)(x+2)
B. 2(x+2)(x+8)
C. 2(x-4)^2
D. The polynomial is irreducible

C. 2(x-4)^2

Step-by-step explanation:

To factorize 2x^2-16x+32

We have to take it step by step and know if it's factorizable then if it is we will look for the answer.

2x^2-16x+32 = 2x² -16x +(2x²)(32)

2x^2-16x+32= 2x² -16x +64x²

I'll ask myself what do i multiply to give me +64x² and add to get -16x.

It's simple.

The answer is -8x

-8x *-8x = 64x²

-8x+-8x = -16x

2x^2-16x+32= 2x² -16x +32

2x^2-16x+32=2x²-8x-8x+32

2x^2-16x+32= 2x(x-4)-8(x-4)

2x^2-16x+32=(2x-8)(x-4)

2x^2-16x+32=2(x-4)(x-4)

2x^2-16x+32=2(x-4)²

12m

step-by-step explanation:

square root means have of a number so have of 3 is 1.5 then multiply it by 8 and you get your answer!