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How many grams of AuCl3, if the compound has 6.3 x10^23 atoms of Cl?

Total mass =  105.8 gram (Approx)

Step-by-step explanation:

Given:

Atoms of Cl = 6.3 × 10²³

Find:

grams of AuCl₃

Computation:

Molecules of AuCl₃ = 6.3 × 10²³ / 3 = 2.1 × 10²³

1 mol of AuCl₃ = 6.022 × 10²³ molecules

Number of mol = 2.1 × 10²³ /  6.022 × 10²³

Number of mol  = 0.348 mol

So,

Molar mass of AuCl₃ = 303.33 g/mol

Total mass = 0.348 mol × 303.33 g/mol

Total mass =  105.8 gram (Approx)

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