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How many grams of AuCl3, if the compound has 6.3 x10^23 atoms of Cl?

105.86 grams of AuCl3, if the compound has 6.3 x10^23 atoms of Cl.

Step-by-step explanation:

We are given that the compound has 6.3 x10^23 atoms of Cl.

To find how many molecules of AuCl3 are in the given compound, we divide the compound by 3, i.e;

 =   molecules of AuCl3.

Now, as we know that 1 mole of AuCI3 has molecules.

So, the moles that our compound has is given by;

      =    =  = 0.349 mole AuCI3

Also, the molar mass of AuCI3 = 303.33 g/mole

So, the molar mass of 0.349 moles AuCI3 =  

                                                                      =  105.86 g

Hence, 105.86 grams of AuCl3, if the compound has 6.3 x10^23 atoms of Cl.