A Ferris wheel is 15 meters in diameter and boarded from a platform that is 1 meters above the ground. The six o'clock position on the Ferris wheel is level with the loading platform. The wheel completes 1 full revolution in 2 minutes. How many minutes of the ride are spent higher than 15 meters above the ground?

The number of minutes of the ride that are spent higher than 15 meters above the ground is 18 minutes.

Step-by-step explanation:

We will use the sin function for the height of the Ferris wheel.

A = amplitude

C = phase shift

D = Vertical shift

2π/B = period

From the provided information:

A = 15/2 = 7.5 m

Compute the Vertical shift as follows:

D = A + Distance of wheel from ground

   = 7.5 + 1

   = 8.5

The equation of height is:

Now at t = 0 the height is, h (t) = 1 m.

Compute the value of C as follows:

So, the complete equation of height is:

Compute the number of minutes of the ride that are spent higher than 15 meters above the ground as follows:

h (t) ≥ 15

Thus, the number of minutes of the ride that are spent higher than 15 meters above the ground is 18 minutes.

answer

a,b, and d

explanation

a reflection angle is more than

but less than;

an angle that measures

is a reflex angle.(true)

an angle that measures less than

is acute.(true)

provided we are considering angles greater or equal to zero.

an acute angle lies in the range.

an obtuse angle is less than 180° but more than 90°

an angle that measures 300° is obtuse (false)

an angle that measures 65° is an acute angle.(true)

b.-4 units

all you   do is count how many times you move