Which transformation(s) can map AMNQ onto APQN?

Given: AMNQ is isosceles with base MQ, and NR and MQ

bisect each other at S.

Prove: AMNS AQNS

We know that AMNQ is isosceles with base MQ. So,

MN - QN by the definition of isosceles triangle. The base

angles of the isosceles triangle, ZNMS and 2NQS, are

congruent by the isosceles triangle theorem. It is also given

that NR and MQ bisect each other at S. Segments

are therefore congruent by the definition of bisector. Thus,

AMNS AQNS by SAS.

N

M

о

S

NS and QS

ONS and RS

MS and RS

MS and QS

R

Step-by-step explanation:

41*67/2=1373.5

step-by-step explanation:

i just used a calculator

x^2 + 81

we can factor this using difference of square binomials.

rewrite the equation:

x^2 - (-81)

factor:

(a^2 - b^2) = (√a^2 + √b^2)(√a^2 - √b^2)

(x^2 - (-81) = (x + √-81)(x - √-81)

we can remove the - from under the radical by multiplying it by i.

(x^2 - (-81) = (x + i√81)(x - i√81)

(x^2 - (-81) = (x + 9i)(x - 9i)

we can check our answer by using foil:

x^2 - 9ix + 9ix - 81i^2

x^2 - 81^2

i^2 = -1

x^2 + 81