2x-5y = 10 Solve for X
ok first i add 5y on both sides
so i get
2x = 10 + 5y
then i divided 2x on both sides
so i get
x = 10 + 5y / 2x
but how am i supposed to divide 10/2x and 5y/2x when they’re different variables??
someone please explain.

x = 5 + 5y/2

Step-by-step explanation:

When you get to 2x = 10 + 5y,

you should divide both sides with 2 only instead of 2x. Because if you divide 2x on both sides, the left side would only remain 1  (since 2x/2x = 1)

2x = 10 + 5y

x = (10 + 5y) / 2

x = 10/2 + 5y/2

x = 5 + 5y/2 .( or  5 + (5/2)y)

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic