In triangle ABC, the measure of angle B is 44degrees more than three times the measure of angle A. The measure of angle C is 61degrees more than the measure of angle A. Find the measure of each angle.

m<A =15, m<B=89, m<C=76

Step-by-step explanation:

A = x

B = 44 + 3x

C = x+61

44 + 3x + x + x + 61 = 180

(you get 5x because you're adding the additional actual value of A to the equation)

now you gotta mush this together

5x + 105 = 180

and now subtract

5x = 75

then divide

x = 15

Great! we found the value of angle A!

now lets plug this in for x in the formulas up top!

B = 44 + 3(15)

B = 44 + 45

B = 89

Ya we're almost done!

C = (15) + 61

C = 76

That's it! that's the value of each angle!

you can check your work by adding the three numbers together to get 180

so lets see

15 + 89 + 76 =

drum roll please

.

.

.

.

180!!

We did it!

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

3+3+3+2*2*2+29*12 = 365

step-by-step explanation: