9) Find the equation of a mirror line to the points Q (1,2) and Q1 (-1,2)

x = 0

Step-by-step explanation:

Q(1, 2 ) and Q1(- 1, 2 ) are both 1 unit from the y- axis

Q is 1 unit to the right of the y- axis and Q1 is 1 unit is 1 unit to the left of the y-axis, thus

The y- axis is the mirror line with equation x = 0

answer:

(-8,7)

explanation:

we know that  

f

(

−

3

)

=

7

therefore, if we wish to get the output as 7, in the function, we need to have our input to be -3.

looking at the function  

f

(

x

+

5

)

, what should the value of x be, such that the input in the function becomes 7?

we simply equate the terms,

x

+

5

=

−

3

x

=

−

8

thus, the point on the new function would be  

(

−

8

,

7

)

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm