PLS HELP ASAP Consider a standard deck of 52 playing cards with 4 suits. If A is the event of drawing a 6 from the deck, and B is the event of drawing a black playing card from the deck, what is the intersection of A and B? (Remember that the black cards are spades and clubs.) A) drawing a 6, a club, or a spade B) drawing the 6 of hearts or the 6 of diamonds C) drawing a 6, a heart, or a diamond D) drawing the 6 of clubs or the 6 of spades

Correct answer is option D) drawing the 6 of clubs or the 6 of spades

Step-by-step explanation:

Given that:

A standard deck of 52 playing cards with 4 suits.

A be the event of drawing a card with 6 from the deck.

B be the event of drawing a black card from the deck.

So, event A will have 4 possibilities i.e. {6 of club, 6 of spade, 6 of diamond, 6 of heart}

And event B will have 26 possibilities {Any card (including 6) from club or spade}

Intersection of two sets is defined as the common elements in the two sets.

As per the explanation of the sets and elements in the sets given above:

If we take intersection it will be:

{6 of club or 6 of spade}

Hence, Correct answer is option D) drawing the 6 of clubs or the 6 of spades

drawing the 6 of clubs or the 6 of spades is the right answer

Step-by-step explanation:

sss (side, side, side)

sas (side, angle, side)

asa (angle, side, angle)

aas (angle, angle, side)

hl (hypotenuse, leg)

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)