(3a^3-5b^3)+blank a^3+blank b^3=(a^3+b^3)

(3a³-5b³)+ (-2)a³ +6b³=(a³+b³)

Step-by-step explanation:

First,  lets remove the brackets.  There is no "-" before the brackets, so we can just remove them at all.

3a³-5b³+ ...a³ +...b³=a³+b³

Now we can joint similar monoms (with variable a)  ( and with variable b) in the left side of equation

3a³+...a³ -5b³ +...b³=a³+b³

Now we can notice that 3a³+...a³=a³    (1)  and

-5b³ +...b³=b³    (2)

Lets find deduct 3a³ from both sides of (1)

...a³= a³-3a³

...a³= -2a³  So instead ... we have to type -2 (-2 is negative sowe type -2 in brackets).

Similarly   lets add 5b³ to both sides of (2)

-5b³ +...b³=b³

-5b³ +5b³ +...b³=b³+5b³

...b³=6b³ So instead ... we have to type 6.

answer: h=5.6 i don't really know how to put into words, so i though i would let you do that. i hope i was able to some

step-by-step explanation:

18 = 6(h)+1/2

18 = 6h+1/2

18-1 = 6h/2

17 = 3h

17/3 = h

h = 5.6