Can you help me with the question please thanks I would really appreciate it thank you

a): m=3

b)n=-4

3):x1=4.59779

Step-by-step explanation:

3(m+2)/5=3 solve brackets first

3m+6/5=3  multiply each side by 5

5(3m+6)/5=15

3m+6=15     subtract 6 from each side

3m+6-6=15-6

3m=9

m=9/3=3

b): 8(n-1)/5=3n-4/2 brackets first

8n-8/5=3n-4/2     cross multiplication

2*(8n-8)=5(3n-4)    

16n-16=15n-20   put n together

16n-15n=-20+16

n=-4

3): x^3-2x=88

it is in the form of ax^3+bx^2+cx+d (a=1,b=0,c=1,d=-88)

the polynomial has no rational roots that can be found

to find the value of x1 , find the zero roots of x when y=0

x^3-2x-88=0

x1=4.59779 which lies between 4 and 5( use polynomiol calculator)

x^3-2x-88 by x-4.59779 ( polynomial calculator)

check : (4.59779)^3-2(4.59779)-88= 0( almost zero)

is there a question here?

step-by-step explanation:

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