The following two-column proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally: Statement Reason 1. Line segment DE is parallel to line segment AC 1. Given 2. Line segment AB is a transversal that intersects two parallel lines. 2. Conclusion from Statement 1. 3. 3. 4. ∠B ≅ ∠B 4. Reflexive Property of Equality 5. 5. 6. BD over BA equals BE over BC 6. Converse of the Side-Side-Side Similarity Theorem Which statement and reason accurately completes the proof? (5 points)

see #7 below

Step-by-step explanation:

7. ΔABC ≅ ΔDBC               7. SAS Similarity Theorem

A much easier way to prove these triangles are similar is to add either #3 or #5:

   Statement           Reason

3. ∠A ≡ ∠D              3. Corresponding Angles Postulate

                      or

5.  ∠C ≡ ∠E              5. Corresponding Angles Postulate

                    to prove

7. ΔABC ≅ ΔDBC    7. AA Similarity Theorem

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

555.99.

step-by-step explanation:

hope this