A sample of 32 boxes of cereal has a sample standard deviation of 0.81 ounces. Construct a 95% confidence interval to estimate the true standard deviation of the filling process for the boxes of cereal. a. (0.656, 1.064)
b. (0.520, 1.100)
c. (0.430, 1.132)
d. (0.729, 0.729)
e None of the above

a. (0.656, 1.064)

Step-by-step explanation:

The sample of cereal is :

n = 32, Standard deviation = 0.81

The confidence interval is 95%

degrees of freedom = df = 31 (n - 1)

= 95%

1 - 0.95 = 0.05

1 -

1 - 0.025 = 0.975

Using chi square distribution we get,

0.656, 1.064

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.

m

step-by-step explanation: