7 A section of a rectangle is shaded.
The area of the shaded section is 63 square units. What
is the value of x?
7
х
9 units
11 units
O 18 units
21 units

This question is incomplete. Please find attached to this solved question, the diagram required to solve this question.

11 units

Step-by-step explanation:

The shaded portion of the rectangle forms the shape of a trapezium

The area of a trapezium = 1/2(a + b)h

From the diagram, we can see than x = b

a = 7 units

b = 7 units

Area of the trapezium = Area of the shaded portion = 63 square units

A = 1/2(a + b)h

63 = 1/2(7 + b)7

63 = 1/2(49 + 7b)

63 × 2 = 49 + 7b

126 - 49 = 7b

7b = 77

b = 77/7

b = 11 units

Since x = b, x = 11 units

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2