A cylinder shaped can needs to be constructed to hold 400 cubic centimeters of soup. The material for the sides of the can costs 0.02 cents per square centimeter. The material for the top and bottom of the can need to be thicker, and costs 0.07 cents per square centimeter. Find the dimensions for the can that will minimize production cost.

the dimensions for the can that will minimize production cost is 9.13 cents

Step-by-step explanation:

The volume of a cylinder  V = π r²h

If we make the height h the subject of the formula; we have :

h = V/ π r²

Given that the volume of the cylinder = 400

Then

h = 400/ π r²

The total cost  will be: 0.02 × 2πrh + 0.07 × 2πr²

= 0.04 (πrh) + 0.14 (πr²)

=  0.04 (πr) + 0.14 (πr²)

= 16/r +  0.14 (πr²)

total cost(c)= 16/r +  0.14 (πr²)

(c') = -16/r² +  0.28 (πr)

Let differentiate (c') with respect to zero (0); then:

-16/r² =  - 0.28 (πr)

r³ = 16/0.28 π

r³ = 18.19

r = 2.63 cm

Recall that:

h = 400/ π r²

h =  400/ π (2.63)²

h =  400/21.73

h = 18.41 cm

From;  total cost =  0.04 (πrh) + 0.14 (πr²)

replacing the value of r and h ; we have:

= 0.04 (π×2.63×18.41) + 0.14 (π × 2.63²)

= 0.04 (152.11) + 0.14 ( 21.73)

= 6.0844 + 3.0422

= 9.1266

≅ 9.13 cents

Therefore; the dimensions for the can that will minimize production cost is 9.13 cents

cant open file sorry!

step-by-step explanation:

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval