Find an equation in standard form for the hyperbola with vertices at (0, ±6) and asymptotes at y = ±3 /7x. y^2/36 - x^2/196 = 1 y^2/196 - x^2/36 = 1 y^2/36 - x^2/49 = 1 y^2/49 - x^2/9 = 1

then, the surface area of the sphere shown in the image is: 256π sq. units!

step-by-step explanation:

the lateral surface area of a sphere is 2πrh where h=2r.

then:

surface area = 4πr^2.

in this case, r=8 units ⇒ surface area = 4π(8 units)^2. = 256π sq. units!

then, the surface area of the sphere shown in the image is: 256π sq. units!

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step-by-step explanation:

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